Lift Upward Acceleration Trick — NTSE Physics in 59 Sec ⚡

 

❓ Question

A man of mass 75 kg stands in a lift.
The lift starts moving upward with an acceleration of 2 m/s².
Find the force exerted on him by the floor.


🖼️ Question Image

Lift Upward Acceleration Trick — NTSE Physics in 59 Sec ⚡


✍️ Short Solution

This is a Newton’s Laws + apparent weight question.
When lift accelerates upward → normal force increases 💯

Lift Upward Acceleration Trick — NTSE Physics in 59 Sec ⚡

🔹 Step 1 — Understand Forces on the Man (MOST IMPORTANT 💯)

Two forces act:

  • Upward → Normal Reaction (N)
  • Downward → Weight (mg)

Since lift is accelerating upward, net force is upward.


🔹 Step 2 — Apply Newton’s Second Law

Nmg=maN - mg = ma

👉 यही सबसे important equation है


🔹 Step 3 — Substitute Values

Mass:

m=75 kgm = 75 \text{ kg}

Acceleration:

a=2 m/s2a = 2 \text{ m/s}^2

Take:

g=10 m/s2g = 10 \text{ m/s}^2
N(75×10)=75×2N - (75 \times 10) = 75 \times 2
N750=150N - 750 = 150
N=900 NN = 900 \text{ N}

🔹 Step 4 — Interpret the Result

👉 Normal force = apparent weight
👉 Lift upward acceleration ⇒ weight increases


✅ Final Answer

900 N\boxed{900\ \text{N}}


⭐ Golden NTSE Insight

  • Lift upward acceleration:
N=m(g+a)N = m(g + a)
  • Lift downward acceleration:
N=m(ga)N = m(g - a)
  • Free fall:
N=0N = 0

🧠 One-line memory:

Lift upar → weight heavy | Lift neeche → weight light

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