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Showing posts with the label Kinematics

Acceleration vs Distance – Find the Power of x (n) | JEE One-Dimensional Motion Doubt | Doubtify JEE

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  ๐Ÿ“ˆ Acceleration as a Function of Distance – Motion in One Dimension | JEE Physics | Doubtify JEE ๐Ÿงฎ Question: The distance x covered by a particle in one-dimensional motion varies with time t as: x² = at² + 2bt + c . If the acceleration of the particle depends on x as x⁻โฟ , where n is an integer, what is the value of n ? ๐Ÿ–ผ️ Question Image: ✅ Detailed Concept & Solution: This is a JEE-level conceptual problem involving the relation between distance, velocity, and acceleration — with a twist of functional dependence. We are given: x² = at² + 2bt + c — (1) To find acceleration and its dependency on x , let’s differentiate both sides of equation (1): Differentiate w.r.t. time t : 2x(dx/dt) = 2at + 2b ⇒ v = dx/dt = (at + b)/x — (2) Now differentiate velocity v w.r.t time to find acceleration: a = dv/dt = d/dt[(at + b)/x] Use quotient rule: a = [a·x - (at + b)(dx/dt)] / x² Plug dx/dt = (at + b)/x from (2): a = [a·x - (at + b)·((at + b)/x)] / x² ⇒ ...

๐Ÿš A Helicopter Drops a Food Packet – Motion in a Straight Line | JEE Physics | Doubtify JEE

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๐ŸŽˆ Balloon Drops Object – Vertical Motion with Initial Velocity | JEE Physics | Doubtify JEE

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๐ŸŽฏ Question: A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground, when the object strikes the ground, was around: (Take g = 10 m/s²)

๐Ÿ’ง Spacing Between Water Droplets – Motion Under Gravity | JEE Physics | Doubtify JEE

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     ๐Ÿ“Œ Question: Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at the 4th second after its fall to the next droplet is 34.3 m . At what rate are the droplets coming from the tap? (Take g = 9.8 m/s²) ๐Ÿ–ผ️ Question Image:

Car Starts & Stops in Time ‘t’ – What’s the Total Distance? | JEE PYQ Solved

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  ๐Ÿงฒ Motion in a Straight Line  |  Physics |  Doubtify JEE ๐Ÿ’ก Question: A car accelerates from rest at a constant rate ฮฑ for some time, after which it decelerates at a constant rate ฮฒ to come to rest. If the total time elapsed is t seconds, the total distance traveled is: ๐Ÿ–ผ️ Question Image: ๐Ÿง  Solution (Image): ๐ŸŽฅ Video Solution: ๐Ÿ” Why this Question is Important: This is a classic and conceptual question from Kinematics , frequently appearing in JEE Main exams. It tests your understanding of uniformly accelerated and retarded motion, and time-division-based distance calculation – a vital part of motion in a straight line. ๐Ÿ“ฉ Have a Doubt? Drop us a mail at  doubtifyqueries@gmail.com  or DM us on  Instagram . Stay consistent. Watch – Pause – Solve – Repeat. Team Doubtify is with you till the finish line! ๐Ÿ’ช

Speed Reduced by 20%, Reaches 16 Minutes Late – Find Actual Time | Motion in Straight Line – JEE Question

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  ๐ŸงชMotion in a Straight Line  | Physics |  JEE Mains ❓ Question: A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed by 20%, and as a result, he reaches his office 16 minutes late. What's the actual/original time he takes to reach his office daily? ๐Ÿ–ผ️ Question Image: ๐Ÿง  Solution (Image): ๐ŸŽฅ Video Solution: ๐Ÿ” Why this Question is Important: This is a frequently asked conceptual problem in  Kinematics  that tests your understanding of the relationship between speed, time, and distance. It’s a perfect example of how real-life reasoning can be applied to JEE Physics problems — and a favorite in  JEE Mains  question banks. ๐Ÿ“ฉ Have a Doubt? Drop us a mail at  doubtifyqueries@gmail.com  or DM us on  Instagram . Stay consistent. Watch – Pause – Solve – Repeat. Team Doubtify is with you till the finish line! ๐Ÿ’ช

A stone is dropped from the top of a building. When it crosses a point 5 m...| Doubtify JEE

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๐Ÿงช Kinematics – Motion in a Straight Line | Physics | JEE Mains ๐Ÿ“Œ Question: A stone is dropped from the top of a building.  When it crosses a point 5 m below the top , another stone starts to fall from a point 25 m below the top , and both stones reach the bottom of the building simultaneously . Find the height of the building . (Take g = 10 m/s²) ๐Ÿ–ผ️ Question Image: ๐Ÿง  Solution (Image): ๐ŸŽฅ Video Solution: ๐Ÿ” Why this Question is Important: This is a  classic conceptual question from Kinematics , commonly asked in  JEE Mains  and other engineering entrance exams. It checks your understanding of  relative motion ,  free fall , and  time equations of motion  – topics that are often mixed to form trick questions. ๐Ÿ“ฉ Have a Doubt? Drop us a mail at  doubtifyqueries@gmail.com  or DM us on  Instagram . Stay consistent. Watch – Pause – Solve – Repeat. Team Doubtify is with you till the finish line! ๐Ÿ’ช