Posts

Showing posts with the label Definite Integral JEE

JEE Main Integration Shortcut — Definite Integrals Made Easy 💡

Image
  ❓ Concept Integration Trick – tan⁻¹ Form in 60 Sec! Whenever you see an integral of the type ∫ sin ⁡ x a + b cos ⁡ 2 x   d x (or with extra terms in the numerator), understand one thing clearly 👇 👉 This is a pure tan⁻¹ game . ✍️ Short Explanation This type of integral is very common in JEE Main + Advanced . The key idea is: sin x dx is the derivative of cos x The denominator becomes a quadratic in cos x Final answer always involves tan⁻¹ 1️⃣ Step 1 — Identify the Pattern Integral of the form: ∫ (something) ⋅ sin ⁡ x a + b cos ⁡ 2 x   d x 👉 Always try substitution : u = cos ⁡ x u = \cos x d u = − sin ⁡ x   d x du = -\sin x\,dx This instantly simplifies the integral. 2️⃣ Step 2 — Apply Substitution From substitution: sin ⁡ x   d x = − d u \sin x\,dx = -du For definite integrals , limits change: x = 0 ⇒ u = cos ⁡ 0 = 1 x = 0 \Rightarrow u = \cos 0 = 1 x = π ⇒ u = cos ⁡ π = − 1 x = \pi \Rightarrow u = \cos \pi = -1 So the integral converts into: ...

If the area of the region { (x, y) : 1 + x² ≤ y ≤ min{ x + 7, 11 − 3x } } is A, then 3A is equal to:

Image
❓ Question:  Find the area of the region { ( x , y ) :    1 + x 2 ≤ y ≤ min ⁡ {   x + 7 ,    11 − 3 x   } } . If this area is A A , compute 3 A 3A . 🖼️ Question Image ✍️ Short Solution Find where the two lines cross each other. Compare x + 7 x+7  and 11 − 3 x 11-3x : x + 7 ≤ 11 − 3 x    ⟺    4 x ≤ 4    ⟺    x ≤ 1. So on ( − ∞ , 1 ] (-\infty,1]  the upper boundary is x + 7 x+7 ; on [ 1 , ∞ ) [1,\infty)  the upper boundary is 11 − 3 x 11-3x . Both meet at x = 1 x=1  with value 8 8 . Find intersection points of parabola with each line. With y = x + 7 y=x+7 : solve 1 + x 2 = x + 7 ⇒ x 2 − x − 6 = 0 1+x^{2}=x+7 \Rightarrow x^{2}-x-6=0  → x = − 2 ,   3 x=-2,\,3 . With y = 11 − 3 x y=11-3x : solve 1 + x 2 = 11 − 3 x ⇒ x 2 + 3 x − 10 = 0 →  x = − 5 ,   2 x=-5,\,2 . Determine the x-range where the parabola lies below the relevant line. For the branch where upper = x + 7 x+7  (valid for x ≤ 1 x\le1 ), the parabola is below this...