A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn/cm and glass-water contact angle ≈ 0°) with 30° inclined with the vertical. The length of water risen in the capillary is:
❓ Question A capillary tube of radius 0.1 mm is partly dipped in water (surface tension = 70 dyn/cm , contact angle ≈ 0° ) with 30° inclination with the vertical . The length of water risen in the capillary is to be found. 🖼️ Question Image ✍️ Short Solution Let’s recall the concept of capillary rise — the upward movement of liquid in a narrow tube due to surface tension. For a vertical tube , h = 2 T cos θ r ρ g But if the tube is inclined at an angle α with the vertical , then the actual length of the water column is longer than the vertical height: l = h cos α 🔹 Given Data Quantity Symbol Value Surface tension T T 70 dyn/cm = 70 × 10⁻³ N/m Radius of tube r r 0.1 mm = 1 × 10⁻⁴ m Contact angle θ \theta 0° ⇒ cosθ = 1 Density of water ρ \rho 1000 kg/m³ Acceleration due to gravity g g 9.8 m/s² Inclination angle α \alpha 30° 🧮 Step-by-Step Calculation Step 1: Calculate vertical height h h h h = 2 T cos θ r ρ g h = \frac{2T \cos \theta}{r \rho g} h = 2 ×...