Balanced Redox Reaction: Mg + HNO₃ → Mg(NO₃)₂ + N₂O + H₂O | JEE Chemistry
⚗️ Balance the Equation: Mg + HNO₃ ⟶ Mg(NO₃)₂ + N₂O + H₂O
❓ Question:
Balance the following chemical equation:
Mg + HNO₃ ⟶ Mg(NO₃)₂ + N₂O + H₂O
This question appears simple at first glance, but it actually requires deep understanding of redox reactions and balancing complex equations.
🎯 Key Concepts Tested:
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Oxidation and reduction processes
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Balancing redox equations using ion-electron method or oxidation number method
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Conservation of mass and conservation of charge
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Identifying oxidizing and reducing agents
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Understanding product formation in acidic medium (presence of HNO₃)
🧠 Step-by-Step Solution Strategy:
Step 1: Identify oxidation states
Let’s determine oxidation states of all elements in reactants and products:
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Mg (0) → Mg²⁺ in Mg(NO₃)₂
→ Oxidation (Mg is losing electrons) -
N in HNO₃: +5
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N in N₂O: +1
→ Reduction (N is gaining electrons)
Step 2: Write unbalanced half-reactions
Oxidation (Mg):
Mg → Mg²⁺ + 2e⁻
Reduction (N):
2 HNO₃ → N₂O + H₂O
Here, we observe a change in oxidation state from +5 to +1.
Each nitrogen gains 4 electrons. Since N₂O has 2 nitrogen atoms, total electrons gained = 8e⁻
So we’ll need 4 magnesium atoms (4 × 2 = 8e⁻) to balance electrons.
Step 3: Balance atoms and charges
After balancing atoms and charges in acidic medium:
Balanced Reaction:
4Mg + 10HNO₃ ⟶ 4Mg(NO₃)₂ + N₂O + 5H₂O
✅ Final Balanced Equation:
4Mg + 10HNO₃ ⟶ 4Mg(NO₃)₂ + N₂O + 5H₂O
🔍 Why This Question is Important:
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Combines multiple concepts: oxidation numbers, acidic medium, electron transfer
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Found in previous year JEE Main & Advanced papers
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Builds confidence in redox reaction types like metal + acid reactions
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Improves balancing speed and reaction intuition – both needed for Physical Chemistry mastery
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