The number of species from the following that are involved in sp³d² hybridization is: [Co(NH₃)₆]³⁺, SF₆, [CrF₆]³⁻, [CoF₆]³⁻, [Mn(CN)₆]³⁻ and [MnCl₆]³⁻
Question: The number of species from the following that are involved in sp³d² hybridization is: [Co(NH₃)₆]³⁺, SF₆, [CrF₆]³⁻, [CoF₆]³⁻, [Mn(CN)₆]³⁻ and [MnCl₆]³⁻ 📷 Question Image: Short Solution (Text): Key idea (VBT quick check) Octahedral complexes can be: d²sp³ (inner-orbital) when strong-field ligands pair electrons in (n−1)d (low spin). sp³d² (outer-orbital) when weak-field ligands don’t pair (high spin), so central atom uses the outer nd orbitals. SF₆ (molecular, not a complex): classic sp³d² around S. Evaluate each species [Co(NH₃)₆]³⁺ Co³⁺: d⁶; NH₃ ~ intermediate/weak-to-borderline but for Co³⁺ it gives low spin (pairing favored) → inner (d²sp³). ❌ SF₆ S uses 3s, three 3p, two 3d → sp³d² (octahedral). ✅ [CrF₆]³⁻ Cr³⁺: d³; F⁻ weak field, but d³ doesn’t need pairing; inner (n−1)d are available → d²sp³ (inner). ❌ [CoF₆]³⁻ Co³⁺: d⁶; F⁻ weak field → high spin , no pairing in (n−1)d → uses outer nd → sp³d² . ✅ [Mn(CN)₆]³⁻ ...