Mohr’s Salt Conductance Trick 🔥 | Kohlrausch Law
❓ Question Two statements are given: Statement I: Mohr's salt is composed of only three types of ions — ferrous, ammonium and sulfate . Statement II: If molar conductance at infinite dilution of Fe²⁺, NH₄⁺ and SO₄²⁻ are x 1 , x 2 , x 3 x_1, x_2, x_3 x 1 , x 2 , x 3 respectively, then molar conductance of Mohr’s salt at infinite dilution is: x 1 + x 2 + 2 x 3 x_1 + x_2 + 2x_3 Determine which statement is correct. 🖼 Question Image ✍️ Short Concept Mohr’s salt is a double salt . Formula: ( N H 4 ) 2 F e ( S O 4 ) 2 ⋅ 6 H 2 O (NH_4)_2Fe(SO_4)_2 \cdot 6H_2O When dissolved in water, it completely dissociates into simple ions . 🔷 Step 1 — Identify the Ions 💯 Mohr’s salt dissociation: ( N H 4 ) 2 F e ( S O 4 ) 2 → F e 2 + + 2 N H 4 + + 2 S O 4 2 − (NH_4)_2Fe(SO_4)_2 \rightarrow Fe^{2+} + 2NH_4^+ + 2SO_4^{2-} So ions present are: Ferrous ion Ammonium ion Sulfate ion Thus Statement I is correct . 🔷 Step 2 — Kohlrausch Law At infinite dilution: ...