Refractive Index Layer Problem ⚡ JEE Shortcut
❓ Question Container contains: Liquid 1: Refractive index μ 1 = 1.2 \mu_1 = 1.2 Height = 60 cm Liquid 2: Refractive index μ 2 = 1.6 \mu_2 = 1.6 Height = H H Viewed from above, apparent shift of bottom = 40 cm Find H H . 🖼 Question Image ✍️ Short Concept For multiple layers: Apparent depth = ∑ real depth μ \text{Apparent depth} = \sum \frac{\text{real depth}}{\mu} Total apparent shift: Shift = Real depth − Apparent depth \text{Shift} = \text{Real depth} - \text{Apparent depth} This is the MOST IMPORTANT relation. 🔷 Step 1 — Write Real Depth 💯 Total real depth: = 60 + H = 60 + H 🔷 Step 2 — Write Apparent Depth Apparent depth = 60 1.2 + H 1.6 \text{Apparent depth} = \frac{60}{1.2} + \frac{H}{1.6} = 50 + H 1.6 = 50 + \frac{H}{1.6} 🔷 Step 3 — Use Shift Formula Given shift = 40 cm Shift = Real depth − Apparent depth \text{Shift} = \text{Real depth} - \text{Apparent depth} 40 = ( 60 + H ) − ( 50 + H 1.6 ) 40 = (60 + H) - ...