List - I List - II (A) Isothermal (I) ΔW (work done) = 0 (B) Adiabatic (II) ΔQ (supplied heat) = 0 (C) Isobaric (III) ΔU (change in internal energy) ≠ 0 (D) Isochoric (IV) ΔU=0
❓ Question Match the following lists correctly: List - I List - II (A) Isothermal (I) ΔW (work done) = 0 (B) Adiabatic (II) ΔQ (supplied heat) = 0 (C) Isobaric (III) ΔU (change in internal energy) ≠ 0 (D) Isochoric (IV) ΔU = 0 🖼️ Question Image ✍️ Short Solution To solve this, let’s recall the key thermodynamic characteristics of each process: Isothermal Process — Temperature remains constant. Hence, internal energy Δ U = 0 ΔU = 0 (since U U depends only on T). Therefore, Δ Q = Δ W ΔQ = ΔW . ✅ Match → (A) → (IV) Adiabatic Process — No heat exchange between system and surroundings. Δ Q = 0 ΔQ = 0 . ✅ Match → (B) → (II) Isobaric Process — Pressure remains constant. Work is done as W = P Δ V W = PΔV . Hence, Δ U ≠ 0 ΔU ≠ 0 because heat and work both can change. ✅ Match → (C) → (III) Isochoric Process — Volume remains constant, Δ V = 0 ΔV = 0 . Thus, work done Δ W = 0 ΔW = 0 . ✅ Match → (D) → (I) 🧮 I...
