Doubtify – JEE Ki Taiyaari, Simple Bhasha Mein

❓ Concept 🎬 Resistance of a Triangular Pyramid — Concept in 59 Sec Wire ko 3D pyramid shape mein bend kar diya… sab segments same length, same material ke… aur puchh liya: 👉 A aur B ke beech equivalent resistance kya hoga? ⚡🤯 Is type ke questions calculation se nahi , symmetry se solve hote hain — bas wahi samajhna hai 🔥 🖼️ Concept Image ✍️ Short Explanation JEE mein jab bhi 3D resistance network dikhe, sabse pehle symmetry dhoondo . 👉 Symmetry mil gayi = problem aadhi solve 😎 🔹 Step 1 — Equal Length ⇒ Equal Resistance (FOUNDATION 💯)** Given: Same material Same length Uniform wire bent into a pyramid 👉 Har edge ka resistance same hoga. Total resistance R R   uniformly distributed hai poore network mein. 📌 Matlab: Har segment = identical resistor 🔹 Step 2 — Use Symmetry First (MOST IMPORTANT 🔥)** Triangular pyramid perfectly symmetric hota hai. Iska matlab: Jo points geometry mein symmetric hain Unka potential bhi same hoga (when current ...

  ❓ Question A wire of total resistance R is bent to form a triangular pyramid (tetrahedron) as shown in the figure, with each segment having the same length (and hence same resistance). The equivalent resistance between points A and B is given as R n . Find the value of n n . 🖼️ Question Image ✍️ Short Solution This is a classic JEE symmetry-based resistance problem . No Kirchhoff, no long equations — sirf symmetry + equivalent paths 🔥 🔹 Step 1 — Count number of equal segments A triangular pyramid (tetrahedron) has: 4 vertices 6 edges The wire of total resistance R R  is bent uniformly into these 6 equal segments . So resistance of each edge : r = R 6​ 🔹 Step 2 — Identify symmetry in the network We are asked resistance between A and B . Important symmetry observation 👇 Points C and D are symmetrically placed with respect to A and B So their potentials will be equal 📌 Hence: No current flows in the wire CD We can safely r...