JEE Main: Hybridisation of SO₂, NO₂⁻ & N₃⁻ — Super Easy Concept 💡
❓ Question In SO 2 \text{SO}_2 , NO 2 − \text{NO}_2^- , and N 3 − \text{N}_3^- , the hybridizations at the central atom are respectively: 🖼️ Question Image ✍️ Short Solution We’ll find hybridization at each central atom using the Steric Number (SN) method: Steric number = Number of σ-bonds + Number of lone pairs on central atom and use: Steric Number Hybridization Example 2 sp BeCl₂ 3 sp² BF₃ 4 sp³ CH₄ 5 sp³d PCl₅ 6 sp³d² SF₆ 🔹 (A) For SO 2 \text{SO}_2 Step 1: Central atom = S Valence electrons of S = 6 Each O atom forms a bond with S; one double bond and one coordinate bond (resonance). → S forms 2 σ-bonds + has 1 lone pair Steric number = 3 → sp² hybridization ✅ Hybridization of S in SO₂ = sp² Geometry: Bent / V-shaped (bond angle ≈ 119°) 🔹 (B) For NO 2 − \text{NO}_2^- Step 1: Central atom = N Valence electrons of N = 5 , plus 1 extra electron (for negative charge) → total 6 N forms 2 σ-bon...