2nd Excited State → Find Atomic Number FAST ⚡
❓ Question In a hydrogen-like ion , the energy difference between the 2nd excited state and the ground state is 108.8 eV . Find the atomic number (Z) of the ion. 🖼️ Question Image ✍️ Short Solution This is a direct Bohr-model energy-level question . No tricks, no approximations — just n-value clarity + Z² scaling 🔥 🔹 Step 1 — Understand ‘2nd Excited State’ (MOST IMPORTANT 💯)** Energy levels in hydrogen-like ions: Ground state → n = 1 n = 1 1st excited state → n = 2 n = 2 2nd excited state → n = 3 n = 3 ✅ 📌 Many students mess up here — 2nd excited ≠ n = 2 🔹 Step 2 — Energy Formula for Hydrogen-like Ion Bohr energy level: E n = − 13.6 Z 2 n 2 eV Where: Z Z = atomic number n n = principal quantum number 🔹 Step 3 — Write Energies of Required Levels Ground state ( n = 1 n=1 ): E 1 = − 13.6 Z 2 2nd excited state ( n = 3 n=3 ): E 3 = − 13.6 Z 2 9 🔹 Step 4 — Energy Difference Given Energy difference: Δ E =...