A dipole with two electric charges of 2 μC magnitude each, with separation distance 0.5 μC, is placed between the plates of a capacitor such that its axis is parallel to an electric field established between the plates when a potential difference of 5 V is applied. Separation between the plates is 0.5 mm. If the dipole is rotated by 30° from the axis, it tends to realign in the direction due to a torque. The value of torque is:
❓ Question A dipole made of two charges of magnitude 2 μ C 2\ \mu\text{C} (equal and opposite) separated by a distance is placed between the plates of a capacitor that has a potential difference V = 5 V V=5\ \text{V} . The plate separation is 0.5 mm 0.5\ \text{mm} . The dipole axis is parallel to the electric field established between the plates. If the dipole is rotated by 30 ∘ 30^\circ from the field axis, it experiences a torque tending to realign it. Find the value of the torque. 🖼️ Question Image ✍️ Short Solution Step 1 — Electric field between capacitor plates Uniform field magnitude: E = V d = 5 V 0.5 × 10 − 3 m = 5 5 × 10 − 4 = 1.0 × 10 4 V/m . Step 2 — Dipole moment Dipole moment magnitude p = q . With q = 2 μ C = 2 × 10 − 6 C q=2\ \mu\text{C}=2\times10^{-6}\ \text{C} and assumed separation s = 0.5 mm = 5 × 10 − 4 m s=0.5\ \text{mm}=5\times10^{-4}\ \text{m} , p = 2 × 1...