JEE Main Set Theory: Identify Relation Properties in 60 Sec 💡
❓ Concept
🎬 Reflexive, Transitive but NOT Symmetric — Easy JEE Trick in 60 Sec
Relations ke chapter mein yeh 3 words sabse zyada confusion create karte hain:
Reflexive, Transitive, Symmetric.
Good news?
👉 Inko samajhne ke liye formula nahi, sirf arrow-logic chahiye 🔥
🖼️ Concept Image
✍️ Short Explanation
JEE mein relations ko ordered pairs se zyada,
arrows on elements ke jaise socho.
Jaise hi arrows clear hue,
✔ property identify
✔ options reject
✔ counting easy
🔹 Step 1 — Reflexive Relation Rule (NON-NEGOTIABLE ⚠️)**
Agar set:
Toh reflexive hone ke liye:
MUST be present.
📌 Inme se ek bhi missing hua
→ relation reflexive hi nahi rahega.
Self-loops = compulsory.
🔹 Step 2 — Transitive Relation Rule (CHAIN EFFECT 🔥)**
Rule:
Arrow language:
-
Agar a → b
-
Aur b → c
👉 Toh a → c compulsory.
📌 Jab bhi arrow-chain dikhe,
third arrow automatically add ho jaata hai.
🔹 Step 3 — What does NOT Symmetric mean?
Symmetric ka matlab hota hai:
So NOT symmetric ka matlab:
👉 At least ONE exception hona chahiye.
Example:
✔️ Bas itna kaafi hai relation ko NOT symmetric banane ke liye.
📌 Zaroori nahi ki sab pairs asymmetric hon —
ek bhi chal jaata hai.
🔹 Step 4 — What the Question is REALLY Asking
Typical JEE question ka hidden meaning hota hai:
Make a relation that:
-
✔ Reflexive (all self-loops included)
-
✔ Transitive (arrow chains complete)
-
❌ NOT symmetric (at least one one-way arrow)
-
✔ Includes a specific pair (like )
-
✔ Total pairs ≤ given limit (e.g. ≤ 6)
👉 Phir possible relations count karne hote hain.
(Concept samajh lo — counting apne aap easy ho jaati hai 😎)
⭐ SUPER SHORT SUMMARY (WRITE IN A BOX)
Reflexive → All MUST be there
Transitive → If & , then
NOT Symmetric → At least one without
✅ Final Takeaway
🧠 Relation Master Rule
-
Self-loops = reflexive
-
Arrow chains = transitive
-
One-way arrow = not symmetric
Agar arrows samajh aa gaye,
👉 Relations ka aadha chapter khatam 😄
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