❓ Question
The atomic number of the element from the following with lowest first ionisation enthalpy is:
- 35
- 19
- 32
- 87
đź–Ľ Question Image
✍️ Short Explanation
This problem is based on:
👉 Periodic trends
👉 First ionisation enthalpy
👉 Metallic character.
Main idea:
and
đź”· Step 1 — Identify the Elements đź’Ż
| Atomic Number | Element |
|---|---|
| 35 | Br |
| 19 | K |
| 32 | Ge |
| 87 | Fr |
đź”· Step 2 — Recall Ionisation Enthalpy Trend
Ionisation enthalpy:
✔ Decreases down the group
✔ Increases across the period
Lowest IE is shown by:
đź”· Step 3 — Compare Given Elements
Bromine (35)
Non-metal.
High ionisation enthalpy.
Potassium (19)
Alkali metal.
Low ionisation enthalpy.
Germanium (32)
Metalloid.
Moderate ionisation enthalpy.
Francium (87)
Bottom-most alkali metal.
Maximum atomic size.
Weakest attraction on outer electron.
Hence:
đź”· Step 4 — Final Identification
đź”· Step 5 — JEE Trap Alert 🚨
❌ Atomic size trend bhool jaana
❌ Metallic character ignore kar dena
❌ Potassium choose kar lena instead of Francium
Remember: