List - I List - II (A) Isothermal (I) ΔW (work done) = 0 (B) Adiabatic (II) ΔQ (supplied heat) = 0 (C) Isobaric (III) ΔU (change in internal energy) ≠ 0 (D) Isochoric (IV) ΔU=0

❓ Question

Match the following lists correctly:

List - I	List - II
(A) Isothermal	(I) ΔW (work done) = 0
(B) Adiabatic	(II) ΔQ (supplied heat) = 0
(C) Isobaric	(III) ΔU (change in internal energy) ≠ 0
(D) Isochoric	(IV) ΔU = 0

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🖼️ Question Image

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✍️ Short Solution

To solve this, let’s recall the key thermodynamic characteristics of each process:

1. Isothermal Process —

   • Temperature remains constant.

   • Hence, internal energy $ΔU = 0$ (since $U$ depends only on T).

   • Therefore, $ΔQ = ΔW$.
     ✅ Match → (A) → (IV)

2. Adiabatic Process —

   • No heat exchange between system and surroundings.

   • $ΔQ = 0$.
     ✅ Match → (B) → (II)

3. Isobaric Process —

   • Pressure remains constant.

   • Work is done as $W = PΔV$.

   • Hence, $ΔU ≠ 0$ because heat and work both can change.
     ✅ Match → (C) → (III)

4. Isochoric Process —

   • Volume remains constant, $ΔV = 0$.

   • Thus, work done $ΔW = 0$.
     ✅ Match → (D) → (I)

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🧮 Image Solution

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✅ Conclusion & Video Solution

✅ Final Matching:

List - I	List - II
(A) Isothermal	(IV) $ΔU = 0$
(B) Adiabatic	(II) $ΔQ = 0$
(C) Isobaric	(III) $ΔU ≠ 0$
(D) Isochoric	(I) $ΔW = 0$

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📘 Concept Recap:

• Isothermal: constant temperature → no change in internal energy.

• Adiabatic: insulated → no heat exchange.

• Isobaric: constant pressure → work done due to volume change.

• Isochoric: constant volume → no work done.