Uniform Acceleration Graphs – Motion from Rest | JEE Physics Graphs | Doubtify JEE

 

๐Ÿš€ Uniform Acceleration Motion Graphs | Kinematics | Doubtify JEE


๐Ÿ“Œ Question:

A particle starts from origin O from rest and moves with a uniform acceleration along the positive x-axis.

๐Ÿ‘‰ Identify all the graphs that correctly represent the motion qualitatively:

  • a = acceleration

  • v = velocity

  • x = displacement

  • t = time

This is a conceptual question testing your understanding of motion graphs!


๐Ÿ–ผ️ Question Image:

Uniform Acceleration Graphs – Motion from Rest | JEE Physics Graphs | Doubtify JEE

๐Ÿง  Solution Image:

๐Ÿงช Explanation:

Let’s break it down using the basic equations of uniformly accelerated motion:

  1. Initial Velocity (u) = 0,

  2. Acceleration (a) = constant > 0

Using equations of motion:

  • v = u + at → v ∝ t

  • x = ut + ½at² → x ∝ t²

  • a = constant


✅ Correct Graphs:

  • a-t graph: Should be a horizontal line (since a is constant).

  • v-t graph: Should be a straight line passing through origin (v ∝ t).

  • x-t graph: Should be a curve opening upward, since x ∝ t² (parabola).

  • v-x graph: Should be a square root function, since v² = 2ax ⇒ v ∝ √x.


❌ Incorrect Graphs (Examples):

  • Any flat v-t (implies constant velocity)

  • Any straight-line x-t (implies zero acceleration)

  • Any a-t sloped or curved (implies non-uniform acceleration)


๐ŸŽฅ Video Solution:




๐Ÿ” Why This Question Is Important:

  • Very common concept in JEE Mains & Advanced

  • Tests if you understand qualitative physics

  • Helps build graphical interpretation skills

  • Often used to frame tricky assertion-reasoning type questions


๐Ÿง  Pro Tip:

Whenever a particle starts from rest and accelerates uniformly:
๐Ÿ‘‰ Displacement curve = parabolic
๐Ÿ‘‰ Velocity-time = linear
๐Ÿ‘‰ Acceleration-time = constant
๐Ÿ‘‰ Always sketch all graphs while practicing to visualize motion better!


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