📺 Subscribe Our YouTube Channels: Doubtify JEE | Doubtify Class 10

Search Suggest

Azeotrope Type Based on Intermolecular Forces

Learn how to identify mixtures that do not form minimum boiling azeotropes based on intermolecular interactions and deviations from Raoult’s law...

❓ Question

Which of the following binary mixtures does not show the behaviour of minimum boiling azeotropes?

C4H9OH+C6H5NH2C_4H_9OH + C_6H_5NH_2
H2O+CH3COCH3H_2O + CH_3COCH_3
CS2+CH3COCH3CS_2 + CH_3COCH_3
CH3OH+CHCl3CH_3OH + CHCl_3

🖼 Question Image

Azeotrope Type Based on Intermolecular Forces


✍️ Short Explanation

This problem is based on:

👉 Azeotropes
👉 Positive and negative deviation
👉 Intermolecular forces.

Main idea:

Minimum boiling azeotropePositive deviation from Raoult’s law\boxed{ \text{Minimum boiling azeotrope} \Rightarrow \text{Positive deviation from Raoult’s law} }

and

Maximum boiling azeotropeNegative deviation\boxed{ \text{Maximum boiling azeotrope} \Rightarrow \text{Negative deviation} }

Azeotrope Type Based on Intermolecular Forces

🔷 Step 1 — Understand Azeotropes 💯

Minimum boiling azeotrope

Occurs when:

AB interactions are weakerA-B \text{ interactions are weaker}

than:

AA and BBA-A \text{ and } B-B

So solution shows:

Positive deviation\boxed{ \text{Positive deviation} }

Boiling point decreases.


Maximum boiling azeotrope

Occurs when:

AB interactions are strongerA-B \text{ interactions are stronger}

So solution shows:

Negative deviation\boxed{ \text{Negative deviation} }

Boiling point increases.


🔷 Step 2 — Check Each Option

Option 1

C4H9OH+C6H5NH2C_4H_9OH + C_6H_5NH_2

Hydrogen bonding gets disturbed.

Interactions become weaker.

Hence:

Positive deviation\boxed{ \text{Positive deviation} }

→ Minimum boiling azeotrope possible.


Option 2

H2O+CH3COCH3H_2O + CH_3COCH_3

Acetone weakens water-water H-bonding.

So:

Positive deviation\boxed{ \text{Positive deviation} }

→ Minimum boiling azeotrope.


Option 3

CS2+CH3COCH3CS_2 + CH_3COCH_3

Weak intermolecular attractions.

Usually shows:

Positive deviation\boxed{ \text{Positive deviation} }

→ Minimum boiling azeotrope.


Option 4

CH3OH+CHCl3CH_3OH + CHCl_3

Strong hydrogen bonding forms between:

O of methanolO \text{ of methanol}

and

H of CHCl3H \text{ of CHCl}_3

So intermolecular attraction becomes stronger.

Hence:

Negative deviation\boxed{ \text{Negative deviation} }

→ Maximum boiling azeotrope.

Thus it does not show minimum boiling behaviour.


🔷 Step 3 — Final Identification

Required mixture:

CH3OH+CHCl3\boxed{ CH_3OH + CHCl_3 }

🔷 Step 4 — JEE Trap Alert 🚨

❌ Positive deviation aur negative deviation confuse kar lena

❌ Hydrogen bonding effect ignore kar dena

❌ Minimum boiling ko stronger attraction se relate kar dena

Remember:

Stronger attractionHigher boiling point\boxed{ \text{Stronger attraction} \Rightarrow \text{Higher boiling point} }

✅ Final Answer

CH3OH+CHCl3\boxed{ CH_3OH + CHCl_3 }

(Option 4)


📚 Related Topics

Post a Comment

Have a doubt? Drop it below and we'll help you out!