Surface Charge Density After Contact – Ratio σ₁/σ₂ | JEE Electrostatics | Doubtify JEE
⚡ Surface Charge Density After Contact – Electrostatics | JEE Physics | Doubtify JEE
📌 Question:
Two metal spheres of radius R and 3R have the same surface charge density σ.
They are brought in contact and then separated.
After separation, let the surface charge densities be σ₁ (for smaller sphere) and σ₂ (for larger sphere).
What is the ratio σ₁ / σ₂?
🖼️ Question Image:
🧠 Solution Image:
🧪 Detailed Concept & Solution:
⚙️ Given:
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Radii: R (small sphere) and 3R (large sphere)
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Initial surface charge density: σ on both spheres
⇒ So initial charges:
🔁 When they are brought in contact:
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Charge redistributes such that potential becomes equal
For a sphere,
Let final charges be Q₁′ and Q₂′ after contact.
So:
Also, total charge is conserved:
Substitute Q₂′ = 3Q₁′:
So:
✅ Now, Surface Charge Density:
So:
✅ Final Answer:
🎥 Video Solution:
🔍 Why This Question is Important:
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Conceptual mix of Electrostatics + Charge Sharing
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Tests your understanding of potential equalization and surface area-based reasoning
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Commonly asked in JEE Main and Advanced
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Mastering this helps in solving problems involving charge redistribution in conductors
🧠 Pro Tip:
Whenever two conducting spheres are connected, their potentials equalize — not charge or surface density. Always start from that principle.
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