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Interference Pattern with Red and Green Light

Learn what happens in Young’s double slit experiment when different color filters are used in each slit. This concept explains coherence and...

❓ Question

In a Young’s double slit experiment, the source is white light.

One of the slits is covered by a red filter and another by a green filter.

In this case:

  1. there shall be an interference pattern for red distinct from that for green.
  2. there shall be no interference fringes and central fringe is given and outer edges is red.
  3. there shall be no interference fringes.
  4. there shall be alternate interference fringes of red and green.

Choose the correct option.


🖼 Question Image

Interference Pattern with Red and Green Light


✍️ Short Explanation

This problem is based on:

👉 Young’s Double Slit Experiment
👉 Coherent sources
👉 Interference of light.

Main idea:

Interference occurs only when waves have:

same frequency and constant phase difference\text{same frequency and constant phase difference}

Interference Pattern with Red and Green Light

🔷 Step 1 — Condition for Interference 💯

For sustained interference:

Sources must be coherent\text{Sources must be coherent}

That means:

✔ Same wavelength/frequency
✔ Constant phase difference


🔷 Step 2 — Analyze the Given Situation

One slit has:

Red light\text{Red light}

Other slit has:

Green light\text{Green light}

Since:

λredλgreen\lambda_{red}\neq\lambda_{green}

their frequencies are different.

Hence the two waves are not coherent.


🔷 Step 3 — Result on Screen

Because the two lights have different frequencies:

No sustained interference pattern forms\text{No sustained interference pattern forms}

Therefore:

No interference fringes are observed\boxed{\text{No interference fringes are observed}}

🔷 Step 4 — About Central Region

At center:

Both colors overlap.

So the central region may appear mixed in color, but no stable bright-dark fringe pattern forms.


🔷 Step 5 — Correct Option

3\boxed{3}

🔷 Step 6 — JEE Trap Alert 🚨

❌ Different colors ke separate fringes assume kar lena

❌ White light YDSE concept directly apply kar dena

❌ Coherence condition ignore kar dena

Remember:

Different frequencies No sustained interference\boxed{ \text{Different frequencies } \Rightarrow \text{No sustained interference} }

✅ Final Answer

3\boxed{3}


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