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Minimum Distance Between Ships Using Relative Velocity

Learn how to find the time at which two moving objects are at minimum distance using relative velocity and vector method. This concept is important...

❓ Question

Ship A is sailing towards north-east with velocity

vA=30i^+50j^ km/hr\vec v_A=30\hat i+50\hat j \text{ km/hr}

where:

i^east,j^north\hat i \rightarrow \text{east}, \quad \hat j \rightarrow \text{north}

Ship B is at a distance of:

80 km east80 \text{ km east}

and

150 km north150 \text{ km north}

of Ship A and is sailing towards west at:

10 km/hr10 \text{ km/hr}

Find after how much time Ship A will be at minimum distance from Ship B.


đź–Ľ Question Image

Minimum Distance Between Ships Using Relative Velocity


✍️ Short Explanation

This problem is based on:

👉 Relative velocity
👉 Minimum distance concept
👉 Dot product condition.

Main idea:

Minimum distance occurs when:

rvrel=0\vec r \cdot \vec v_{rel}=0

đź”· Step 1 — Initial Relative Position đź’Ż

Take Ship A as reference.

Ship B is:

80 km east80 \text{ km east}

and

150 km north150 \text{ km north}

So relative position vector:

r0=80i^+150j^\vec r_0=80\hat i+150\hat j

đź”· Step 2 — Relative Velocity

Velocity of Ship A:

vA=30i^+50j^\vec v_A=30\hat i+50\hat j

Velocity of Ship B:

vB=10i^\vec v_B=-10\hat i

Relative velocity of B with respect to A:

vBA=vBvA\vec v_{BA}=\vec v_B-\vec v_A
=(1030)i^+(050)j^=(-10-30)\hat i+(0-50)\hat j
=40i^50j^=-40\hat i-50\hat j

đź”· Step 3 — Relative Position After Time tt

r=r0+vBAt\vec r=\vec r_0+\vec v_{BA}t
=(8040t)i^+(15050t)j^=(80-40t)\hat i+(150-50t)\hat j

đź”· Step 4 — Condition for Minimum Distance

At minimum distance:

rvBA=0\vec r \cdot \vec v_{BA}=0

So:

[(8040t)i^+(15050t)j^](40i^50j^)=0[(80-40t)\hat i+(150-50t)\hat j] \cdot (-40\hat i-50\hat j)=0

đź”· Step 5 — Solve Equation

40(8040t)50(15050t)=0-40(80-40t)-50(150-50t)=0
3200+1600t7500+2500t=0-3200+1600t-7500+2500t=0
4100t=107004100t=10700
t=10741t=\frac{107}{41}
t2.61 hrt\approx2.61 \text{ hr}

đź”· Step 6 — JEE Trap Alert 🚨

❌ Relative velocity wrong lena

❌ Minimum distance formula directly bhool jaana

❌ Position vector ka direction reverse kar dena

Remember:

Minimum distance condition:

rvrel=0\boxed{\vec r \cdot \vec v_{rel}=0}

✅ Final Answer

10741 hr2.61 hr\boxed{\frac{107}{41}\text{ hr}\approx2.61\text{ hr}}


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