❓ Question
For decomposition of steam:
Kp=8.0×10−3
at:
Total pressure at equilibrium:
Degree of dissociation of water is:
(Nearest integer value)
Assume:
đź–Ľ Question Image
✍️ Short Explanation
This problem is based on:
👉 Degree of dissociation
👉 Equilibrium constant
👉 Partial pressures.
Main idea:
For decomposition:
if initial moles of water are 1:
đź”· Step 1 — Assume Initial Moles đź’Ż
Take initially:
Let degree of dissociation be:
Reaction:
Equilibrium Moles
| Species | Initial | Change | Equilibrium |
|---|
| 1 |
|
|
| | 0 |
|
|
| | 0 | | |
đź”· Step 2 — Total Moles at Equilibrium
Given:
So:
đź”· Step 3 — Partial Pressures
Total pressure:
Thus:
đź”· Step 4 — Apply Expression
Substitute:
Thus:
đź”· Step 5 — Solve for
Thus:
Nearest integer:
đź”· Step 6 — JEE Trap Alert 🚨
❌ Total moles calculate karte time:
bhool jaana
❌ Partial pressure directly mole maan lena without total pressure
❌ expression galat likh dena
Remember:
✅ Final Answer
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