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Quantum Numbers and Orbitals Statement Analysis

Learn how to analyze electronic configuration and quantum numbers for an element with atomic number 9. This helps identify correct statements in JEE..

❓ Question

Correct statements for an element with atomic number:

99

are:

A.

There can be 5 electrons for which:

ms=+12m_s=+\frac12

and 4 electrons for which:

ms=12m_s=-\frac12

B.

There is only one electron in pp-orbital.


C.

The last electron goes to orbital with:

n=2 and l=1n=2 \text{ and } l=1

D.

The sum of angular nodes of all the atomic orbitals is 1.

Choose the correct answer:

  1. A, C and D only
  2. C and D only
  3. A and C only
  4. A and B only

đź–Ľ Question Image

Quantum Numbers and Orbitals Statement Analysis


✍️ Short Explanation

This problem is based on:

👉 Electronic configuration
👉 Quantum numbers
👉 Angular nodes.

Main idea:

Atomic number:

99

corresponds to:

F(Fluorine)\boxed{ F(Fluorine) }

Electronic configuration:

1s22s22p51s^2\,2s^2\,2p^5

Quantum Numbers and Orbitals Statement Analysis

đź”· Step 1 — Check Statement A đź’Ż

Configuration:

1s22s22p51s^2\,2s^2\,2p^5

Using Hund’s rule:

In:

2p52p^5

three electrons first occupy separately with parallel spins.

Total spin distribution becomes:

5 electrons with ms=+125 \text{ electrons with } m_s=+\frac12

and

4 electrons with ms=124 \text{ electrons with } m_s=-\frac12

Hence:

Statement A is TRUE\boxed{ \text{Statement A is TRUE} }

đź”· Step 2 — Check Statement B

Configuration contains:

2p52p^5

Thus there are:

5

electrons in pp-orbitals.

So statement:

“Only one electron in pp-orbital”

is false.

Statement B is FALSE\boxed{ \text{Statement B is FALSE} }

đź”· Step 3 — Check Statement C

Last electron enters:

2p

orbital.

For pp-orbital:

l=1l=1

and principal quantum number:

n=2n=2

Thus:

Statement C is TRUE\boxed{ \text{Statement C is TRUE} }

đź”· Step 4 — Check Statement D

Angular nodes:

=l=l

Orbitals occupied are:

1s1s

l=0l=0

Angular nodes:

00

2s2s

l=0l=0

Angular nodes:

00

2p2p

l=1l=1

Angular nodes:

11

Total angular nodes:

0+0+1=10+0+1=1

Hence:

Statement D is TRUE\boxed{ \text{Statement D is TRUE} }

đź”· Step 5 — Final Correct Statements

A, C, D\boxed{ A,\ C,\ D }

đź”· Step 6 — JEE Trap Alert 🚨

2p52p^5 ko one electron samajh lena

❌ Angular nodes formula bhool jaana

❌ Last electron orbital identify na kar paana

Remember:

Angular nodes=l\boxed{ \text{Angular nodes}=l }

✅ Final Answer

A, C and D only

(Option 1)


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