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Which Pair Has Different Dimensions JEE Main PYQ

Solve this JEE Main Physics question based on dimensional analysis. Compare the dimensions of pressure and Young's modulus, surface tension and

 

❓ Question

The pair of physical quantities not having the same dimensions is:

  1. Pressure & Young's Modulus
  2. Surface Tension & Impulse
  3. Torque & Energy
  4. Angular Momentum & Planck's Constant
Which Pair Has Different Dimensions JEE Main PYQ

✍️ Solution

(1) Pressure & Young's Modulus

Pressure is

P=FAP=\frac{F}{A}
[P]=[MLT2][L2][P]=\frac{[MLT^{-2}]}{[L^2]}
[P]=[ML1T2]\boxed{[P]=[ML^{-1}T^{-2}]}

Young's modulus is

Y=StressStrainY=\frac{\text{Stress}}{\text{Strain}}

Since strain is dimensionless,

[Y]=[ML1T2]\boxed{[Y]=[ML^{-1}T^{-2}]}

Thus, both have the same dimensions.


(2) Surface Tension & Impulse

Surface tension is

T=FlT=\frac{F}{l}
[T]=[MLT2][L][T]=\frac{[MLT^{-2}]}{[L]}
[T]=[MT2]\boxed{[T]=[MT^{-2}]}

Impulse is

J=F×tJ=F\times t
[J]=[MLT2][T][J]=[MLT^{-2}][T]
[J]=[MLT1]\boxed{[J]=[MLT^{-1}]}

Thus, they do not have the same dimensions.

Option 2\boxed{\text{Option 2}}

(3) Torque & Energy

Torque is

Ď„=F×r\tau=F\times r
[Ď„]=[MLT2][L][\tau]=[MLT^{-2}][L]
[Ď„]=[ML2T2]\boxed{[\tau]=[ML^2T^{-2}]}

Energy is

E=F×dE=F\times d
[E]=[ML2T2]\boxed{[E]=[ML^2T^{-2}]}

Thus, both have the same dimensions.


(4) Angular Momentum & Planck's Constant

Angular momentum is

L=mvrL=mvr
[L]=[M][LT1][L][L]=[M][LT^{-1}][L]
[L]=[ML2T1]\boxed{[L]=[ML^2T^{-1}]}

From

E=hνE=h\nu
h=Eνh=\frac{E}{\nu}
[h]=[ML2T2][T1][h]=\frac{[ML^2T^{-2}]}{[T^{-1}]}
[h]=[ML2T1]\boxed{[h]=[ML^2T^{-1}]}

Thus, both have the same dimensions.

Which Pair Has Different Dimensions JEE Main PYQ


✅ Final Answer

Option 2 — Surface Tension & Impulse
\boxed{\text{Option 2 — Surface Tension \& Impulse}}

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