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Errors in Measurement PYQ Solved Fast

Learn a quick shortcut to calculate maximum fractional error in a physical quantity involving powers of independent variables. This JEE Main Physics

 

❓ Question

A quantity QQ is formulated as

Q=X2Y3/2Z2/5Q=X^{-2}Y^{3/2}Z^{-2/5}

where XX, YY, and ZZ are independent parameters having fractional errors:

ΔXX=0.1,ΔYY=0.2,ΔZZ=0.5\frac{\Delta X}{X}=0.1,\qquad \frac{\Delta Y}{Y}=0.2,\qquad \frac{\Delta Z}{Z}=0.5

Find the maximum fractional error in
Q
.

Errors in Measurement PYQ Solved Fast


✍️ Solution

For a quantity of the form

Q=XaYbZcQ=X^aY^bZ^c

the maximum fractional error is

ΔQQ=aΔXX+bΔYY+cΔZZ\frac{\Delta Q}{Q} = |a|\frac{\Delta X}{X} + |b|\frac{\Delta Y}{Y} + |c|\frac{\Delta Z}{Z}

Here,

a=2,b=32,c=25a=-2,\qquad b=\frac32,\qquad c=-\frac25

Therefore,

ΔQQ=2(0.1)+32(0.2)+25(0.5)\frac{\Delta Q}{Q} = |-2|(0.1) + \left|\frac32\right|(0.2) + \left|-\frac25\right|(0.5)
=2(0.1)+32(0.2)+25(0.5)= 2(0.1) + \frac32(0.2) + \frac25(0.5)
=0.2+0.3+0.2= 0.2+0.3+0.2
ΔQQ=0.7\boxed{\frac{\Delta Q}{Q}=0.7}
Errors in Measurement PYQ Solved Fast

✅ Final Answer

0.7\boxed{0.7}

or equivalently,

70%\boxed{70\%}

Key Idea

For maximum error, always add the absolute contributions of all independent variables. Hence negative powers such as 2-2 and 25-\frac25 also contribute positively to the maximum fractional error.

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