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Polynomial Divisibility Counting Problem

Learn how to solve polynomial divisibility problems by using factor theorem, remainder theorem, and coefficient comparison techniques.

 

❓ Question

Let

S={x3+ax2+bx+c  ;  a,b,cN, a,b,c20}S=\{x^3+ax^2+bx+c \; ; \; a,b,c\in\mathbb N,\ a,b,c\le 20\}

Then the number of polynomials in SS which are divisible by

x2+2x^2+2

is:

  1. 20
  2. 10
  3. 6
  4. 4
Polynomial Divisibility Counting Problem

✍️ Short Explanation

If a cubic polynomial is divisible by x2+2x^2+2, then:

x3+ax2+bx+c=(x2+2)(x+k)x^3+ax^2+bx+c=(x^2+2)(x+k)

for some integer kk.

Now compare coefficients.

Polynomial Divisibility Counting Problem


đź”· Step 1 — Expand

(x2+2)(x+k)(x^2+2)(x+k)
=x3+kx2+2x+2k= x^3+kx^2+2x+2k

Comparing with

x3+ax2+bx+cx^3+ax^2+bx+c

gives

a=k,b=2,c=2ka=k,\qquad b=2,\qquad c=2k

đź”· Step 2 — Apply Conditions

Given:

a,b,cN,a,b,c20a,b,c\in\mathbb N,\qquad a,b,c\le 20

Since

a=ka=k

and

c=2kc=2k

we need

kNk\in\mathbb N

and

2k202k\le 20
k10k\le 10

Thus

k=1,2,3,,10k=1,2,3,\ldots,10

Total values of kk:

1010

Each value gives a unique polynomial.


✅ Final Answer

10\boxed{10}

Option (2)


đź”· JEE Shortcut

Whenever a cubic is divisible by a quadratic:

Cubic=(Quadratic)(Linear)\text{Cubic}=(\text{Quadratic})(\text{Linear})

Write:

(x2+2)(x+k)(x^2+2)(x+k)

and compare coefficients directly. This avoids using roots ±i2\pm i\sqrt2 and makes the counting question a 10-second problem.


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