❓ Concept Question
How do ligand strength and -electron configuration decide hybridization and magnetic nature in coordination compounds?
🖼 Concept Image
✍️ Short Concept
This concept is based on:
👉 Oxidation state of central metal
👉 configuration
👉 Strong field vs weak field ligands
👉 Hybridization in octahedral complexes.
🔷 Step 1 — Oxidation State of Metal 💯
First step in coordination compounds:
👉 Calculate oxidation state of central metal.
Formula logic:
This helps determine:
🔷 Step 2 — d-Electron Configuration
After oxidation state:
👉 Write configuration.
Examples:
This decides number of possible unpaired electrons.
🔷 Step 3 — Ligand Strength
Ligands decide electron pairing.
Strong Field Ligands
👉 Cause pairing of electrons
Weak Field Ligands
👉 Do not cause pairing
🔷 Step 4 — Hybridization in Octahedral Complex
For strong field ligands:
👉 Inner orbital complex
For weak field ligands:
👉 Outer orbital complex
🔷 Step 5 — Magnetic Nature
If unpaired electrons present:
👉 Paramagnetic
If all electrons paired:
👉 Diamagnetic
🔷 Step 6 — JEE Trap Alert 🚨
❌ Strong ligand dekh ke direct diamagnetic assume kar lena
❌ configuration galat nikal dena
❌ ko strong field ligand maan lena
❌ Hybridization aur magnetic nature confuse kar dena
Remember:
✅ Final Takeaway
For coordination compound problems:
Always:
⭐ Golden JEE Insight
If ligand is strong:
If ligand is weak: