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LCM × HCF = Product of Numbers Explained

Learn how to solve Exercise 1.1 Question 4 from Class 10 Maths Chapter 1 Real Numbers using the relation between HCF and LCM. Understand the concept..

 

❓ Question

Given that:

HCF(306,657)=9\text{HCF}(306,657)=9

Find:

LCM(306,657)\text{LCM}(306,657)

🖼️ Solution Image

LCM × HCF = Product of Numbers Explained


✍️ Short Solution

This is a direct HCF–LCM relation question.

Use the formula:

LCM×HCF=a×b\text{LCM} \times \text{HCF} = a \times b

🔹 Step 1 — Write the Formula

For any two integers aa and bb:

LCM×HCF=a×b\text{LCM} \times \text{HCF} = a \times b

🔹 Step 2 — Substitute Values

Given:

HCF=9\text{HCF} = 9
a=306,b=657a = 306,\quad b = 657

So,

LCM×9=306×657\text{LCM} \times 9 = 306 \times 657

🔹 Step 3 — Find LCM

LCM=306×6579\text{LCM} = \frac{306 \times 657}{9}
LCM=2010429\text{LCM} = \frac{201042}{9}
LCM=22338\text{LCM} = 22338

✅ Final Answer

LCM(306,657)=22338\boxed{\text{LCM}(306,657)=22338}


⭐ Key Insight

For any two numbers:

LCM×HCF=Product of the numbers\boxed{\text{LCM} \times \text{HCF} = \text{Product of the numbers}}

🧠 Memory Line:

LCM nikaalne ke liye product ko HCF se divide karo

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