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GP Product and Sum Relation Trick

Learn how to solve geometric progression problems involving product of terms and range of sums using algebraic transformations. This shortcut helps...

 

❓ Concept Question

In a G.P., if the product of first three terms is fixed, how can we find the range of the sum of first three terms?


đź–Ľ Concept Image

GP Product and Sum Relation Trick


✍️ Short Concept

This concept is based on:

👉 Geometric Progression (G.P.)
👉 Middle term property
👉 AM-GM inequality
👉 Range of expressions.

Main idea:

For three terms in G.P.:

ar, a, ar\boxed{ \frac ar,\ a,\ ar }

their product becomes:

(ar)(a)(ar)=a3\boxed{ \left(\frac ar\right)(a)(ar)=a^3 }

So ratio cancels automatically.


đź”· Step 1 — Standard Form of 3 G.P. Terms đź’Ż

Three terms of G.P. are generally written as:

ar, a, ar\boxed{ \frac ar,\ a,\ ar }

Why this form?

✔ Middle term stays clean

✔ Ratio handling becomes easy

✔ Product simplifies directly


đź”· Step 2 — Product Trick

For these three terms:

(ar)a(ar)\left(\frac ar\right)\cdot a \cdot(ar)
=a3=a^3

Important observation:

Common ratio r cancels out\boxed{ \text{Common ratio } r \text{ cancels out} }

Thus:

✔ Fixed product ⇒ fixed middle term.


đź”· Step 3 — Sum of Three Terms

Sum becomes:

S=ar+a+arS=\frac ar+a+ar

Take aa common:

S=a(r+1+1r)S=a\left(r+1+\frac1r\right)

So the entire range depends on:

r+1r\boxed{ r+\frac1r }

đź”· Step 4 — Golden AM-GM Trick ✨

For positive rr:

r+1r2\boxed{ r+\frac1r\ge2 }

Equality occurs at:

r=1r=1

Therefore:

Smin=a(2+1)=3aS_{\min}=a(2+1)=3a

This gives the minimum possible sum.


đź”· Step 5 — JEE Observation 🚨

Whenever question says:

✔ Product of G.P. terms fixed

Immediately think:

Middle term fixed\boxed{ \text{Middle term fixed} }

Then reduce sum into:

r+1rr+\frac1r

and apply:

x+1x2\boxed{ x+\frac1x\ge2 }

✅ Final Takeaway

For three G.P. terms:

ar, a, ar\boxed{ \frac ar,\ a,\ ar }

Important formulas:

Product

=a3\boxed{ =a^3 }

Sum

=a(r+1+1r)\boxed{ =a\left(r+1+\frac1r\right) }

Key inequality

r+1r2\boxed{ r+\frac1r\ge2 }




🌟 Golden JEE Insight

Most G.P. range questions reduce to:

x+1x\boxed{ x+\frac1x }

Once you spot this pattern:

✔ Minimum value questions become very fast

✔ No need for lengthy calculus


📚 Related Topics

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