JEE Main: Shortest Distance Given → Find α Smartly 💡
❓ Concept
🎬 Shortest Distance in 3D (α-based) in 59 Sec
JEE 3D geometry mein jab shortest distance diya ho
aur α parameter direction ratios mein aa jaaye —
samajh lo cross product ka real test start ho gaya hai 🔥
🖼️ Concept Image
✍️ Short Explanation
Shortest distance problems formula-based hote hain,
lekin jab parameter (α) involve ho, toh goal hota hai:
👉 SD ko α ke function mein convert karna
👉 Given distance se equation banana
👉 α ke possible values nikaalna (ya unka sum)
🔹 Step 1 — Lines in Symmetric Form
Agar line di ho:
Toh:
-
Direction vector
-
Point on line
Similarly, second line ke liye:
and point .
📌 Agar α direction ratios mein hai,
toh α pe depend karega.
🔹 Step 2 — Shortest Distance Formula (CORE 🔥)**
For skew lines, shortest distance:
⚠️ Important:
-
Yeh formula sirf skew lines ke liye valid hai
-
Parallel ya intersecting lines mein SD = 0 ya different logic
🔹 Step 3 — Role of Parameter (α)
Jab α aata hai:
-
-
-
Numerator & denominator dono α pe depend karte hain
👉 Isliye:
🔹 Step 4 — Use the Given Shortest Distance
Agar question bole:
Toh:
Next steps:
1️⃣ Square both sides (modulus & root hat jaata hai)
2️⃣ Simplify
3️⃣ Quadratic equation in α mil jaati hai
Usually:
🔹 Step 5 — Final JEE Insight (SMART MOVE 😎)**
Agar question pooche:
“Sum of all possible values of α”
Toh:
-
Roots =
-
Sum of roots:
👉 Individual α nikaalne ki zarurat hi nahi!
✅ Final Takeaway
🧠 Shortest Distance (α-based) Golden Rules
-
Direction vectors pehle identify karo
-
Cross product nikaalo
-
SD formula lagao
-
Given value se equation banao
-
Sum of α = −B/A
Is trick se parameter wale 3D questions JEE mein lightning-fast ho jaate hain ⚡
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