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Refractive Index and Optical Density Assertion Reason

Understand the relation between refractive index and optical density and whether it depends on mass density. This helps solve assertion reason...

 

❓ Question

Given below are two statements:

  • Assertion (A): Refractive index of glass is higher than that of air.

  • Reason (R): Optical density of a medium is directly proportionate to its mass density which results in a proportionate refractive index.


đź–Ľ️ Question Image

Given below are two statements :  Assertion (A): Refractive index of glass is higher than that of air. Reason (R): Optical density of a medium is directly proportionate to its mass density which results in a proportionate refractive index.


✍️ Short Explanation

This problem is based on:

👉 Refractive index
👉 Optical density
👉 Assertion-Reason concept.

Main idea:

n=cv\boxed{ n=\frac{c}{v} }

Higher refractive index means light travels slower in that medium.

Refractive Index and Optical Density Assertion Reason


đź”· Step 1 — Check Assertion (A) đź’Ż

For air:

n1n \approx 1

For glass:

n1.5n \approx 1.5

Thus:

nglass>nair\boxed{ n_{glass}>n_{air} }

Hence Assertion (A) is correct.


đź”· Step 2 — Check Reason (R)

Reason says:

“Optical density is directly proportional to mass density.”

This statement is NOT always true.

✔ Optical density depends on how light interacts with medium.

✔ It is not directly determined by mass density alone.

Example:

Some optically denser substances may have lower mass density.

Thus Reason (R) is incorrect.


đź”· Step 3 — Final Conclusion

✔ Assertion (A) → Correct

✔ Reason (R) → Incorrect

Therefore:

(A) is correct but (R) is not correct\boxed{ \text{(A) is correct but (R) is not correct} }


đź”· Step 4 — JEE Trap Alert 🚨

❌ Optical density ko mass density samajh lena

❌ Refractive index ko only physical density se relate kar dena

Remember:

Optical densityMass density\boxed{ \text{Optical density} \neq \text{Mass density} }


✅ Final Answer

(A) is correct but (R) is not correct\boxed{ \text{(A) is correct but (R) is not correct} }

(Option 2)


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